The travels to a nearby planet and signals the galaxy sends out a smaller craft

Question

The travels to a nearby planet and signals the galaxy sends out a smaller craft that (a) to the planet its findings back. The proper time tor the trip from the on is measured board of the Enterprise b) on board of the explorer craft (c) on Earth (d) outside both the Enterprise and the explorer craft. (e) At the center of the galaxy. 24. Following with question 23: The explorer craft is moving at 0.60c with respect to the Enterprise If the crew of the Enterprise measures takes 3.75 hours to reach the How long that the craft (a) a time has passed for the explorer craft? 0.333 h (d) 4.69 h (b) 2.37 h (e) 5.95 h (c) 3.00 h 25. A muon is a subatomic particle that, when at rest in a laboratory, is observed to decay 2 us after created. However, when moving at a certain high speed, the time to decay is measured to be 14 us. How fast is the muon moving with respect to the laboratory? (a) 0.99c (d) 0.86c (b) 0.93c (e) 0.82c (c) 1.01 Note: this type of measurement has been confirmed experimentally and is the confirmation that time dilation does happen. Questions 26 and 27. A spaceship flies past Mars with a speed of 0.985 with respect to the surface of Mars. When the spaceship is directly overhead, a light signal on the surface blinks on and off According to the equipment on the surface, the light stayed on for 75.0 us. 26. Who measures the proper time for the time the light stayed on? (a) The pilot of the spaceship (b) The equipment on the surface 27. What is the duration of the light signal according to the pilot of the spaceship? (a) 612 us (b) 434 us (c) 5000 us (d) 12.9 us 28. A car is measured to be 18 ftlong when at rest. If the car were to move at a constant 0.3c, how long would it be measured to be? (a) 12.1 ft (d) 17.2 ft (b) 13.4 ft (e) 18.9 ft (c) 16.5 ft

Explanation / Answer

23.

The proper time would be measured by the explorer craft.

So, the correct option is (b)

***************************************************************************************************

24.

The Enterpsrie measures the improper time t', while the explorer craft measures proper time t. So,

t' =  t/[1 - (0.6c)2/c2]1/2 = t/0.8

or, 3.75h = t/0.8

or, t = 3 h

So, the correct option is (c)

***************************************************************************************************

25.

We use the formula,

t' =  t/[1 - (v)2/c2]1/2

or, 14µs = 2µs/[1 - (v)2/c2]1/2

or, [1 - (v)2/c2]1/2 = 1/7

or, 1 - (v)2/c2 = 1/49

or, v = 0.99c

So, the correct option is (a)

***************************************************************************************************

26.

proper time is measured by the equipment on the surface.

So, correct option is (b)

***************************************************************************************************

27.

the pilot of the ship measures the improper time interval  t', while the surface equipment measures proper time t and we have,

t' =  t/[1 - (v)2/c2]1/2

or, t' = (75µs)/[1 - (0.985c)2/c2]1/2

or, t' = 434.64µs

So, the correct option would be (b)

***************************************************************************************************

28.

L' = L[1 - (0.985c)2/c2]1/2 = 18ft[1 - (0.3c)2/c2]1/2

or, L' = 17.2ft

So, the correct option is (d)

***************************************************************************************************
This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification, modification or correction, feel free to ask.....

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.