A long, straight wire carrier a current of 3.00 Amps. A proton is traveling in t

Question

A long, straight wire carrier a current of 3.00 Amps. A proton is traveling in the vicinity of the wire. At some instant, a proton is 5.00 em from the wire and traveling with a speed of 6.00 times 10^5 m/s parallel to the wire in the direction opposite to the current (Assume that the current runs right to left and the proton is below the wire). a) What is the magnitude of the magnetic field at that point due to the wire? b) What is the direction of the magnetic field at that point (into the page, out of the page, upwards, downwards, or something else)? c) What is the magnitude of the magnetic force on the proton at that point? d) What is the direction of the magnetic force an the proton at that point (into the page, out of the page, upwards, downwards, or something else)?

Explanation / Answer

(a) Magnetic field=uI/2*pi*r

r=0.05 m

so magnetic field=1.2*10^(-5) T

(b) direction=down the plane of paper

(c)force=evB=1.152*10^(-8) N

(d)direction=i*(-k)=-j

means downwards

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