Find the magnitude of the magnetic flux through the floor of a house that measur

Question

Find the magnitude of the magnetic flux through the floor of a house that measures 22-m by 18-m. Assume that the Earth's magnetic field at the location of the house has a horizontal component of 2.6 times 10^-5 T pointing north, and a downward vertical component of 4 2 times 10^-5 T. A square antenna, used for AM radio signals, is 0.5 M on a side, and has 35 turns. If the magnetic field from the radio waves changes at a rate of 9.2 times 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop?

Explanation / Answer

here,

the area of floor , A = 22 * 18 = 396 m^2

the vertical component of magnetic feild , By = 4.2 * 10^-5 T

the magnitude of magnetic flux , phi = B * area * cos(theta)

phi = 396 * 4.2 * 10^-5 T.m^2

phi = 1.66 * 10^-2 T.m^2

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