Two masses, m_1 and m_2 are connected to each other. Mass m_1 slides with fricti

Question

Two masses, m_1 and m_2 are connected to each other. Mass m_1 slides with friction on the table surface. Both masses have acceleration of magnitude a. How does the tension in the string compare to the weight of m_2? The tension is equal to m_2 g. The tension is larger than m_2 g. The tension is smaller than m_2 g. It depends on if m_1 is smaller than m_2 It depends on if m_1 is larger than m_2. None of the above Find the speed of the system after m_2, starting from rest, moves through some distance, h. The surface that m_1 rests on is rough. v = Squareroot 2gh m_2 + mu _gm_1/m_1 + m_2 v = Squareroot 2gh m_2 + mu _gm_1/m_1 - m_2 v = Squareroot 2gh m_2 - mu _gm_1/m_1 + m_2 v = Squareroot 2gh m_2 - mu _gm_1/m_1 - m_2 v = 2gh Squareroot m_2 - mu _gm_1/m_1 + m_2 v = Squareroot 2gh m_2 - mu _gm_1/m_1 + m_2

Explanation / Answer

13) option c is correct.

Tension is smaller because net force on m2 has to be downward.

14) lets find acceleration a

m2a = m2g -T

m1a=T - um1g

a = g*(m2-um1)/(m1+m2)

v = sqrt(2ah)

option c is correct

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