An electron is placed at the position marked by the dot. The force on the electr

Question

An electron is placed at the position marked by the dot. The force on the electron is a. .. to the left. b. ..to the right c. ..Zero. d. ..There's not enough information to tell. Rank in order, from largest to smallest, the forces F_a to F_e a proton would experience if placed at points a - e in this very long, narrow parallel-plate capacitor. a. F_a = F_b = F_c = F_d = F_e b. F_a = F_b > F_c > F_d = F_e| c. F_a = F_b = F_d = F_e > F_c d. F_e > F_d > F_c > F_b > F_a e. F_e = F_d > F_c > F_a = F_b The total electric flux through the dotted box in the above problem is: a. 0 Nm^2/C. b. 1 Nm^2/C. c. 2 Nm^2/C. d. 4 Nm^2/C. e. 6 Nm^2/C

Explanation / Answer

1. Force F=qVxE =-eVxE

As the charge of electron is negative , force will be opposite to electric feild.

So, (1.a).force on electron to the left

2. As the electric feild inside the capacitor is constant. Force on all elecron is same,

correct option: 2.a

3. Total electric flux will be zero as the electric feild inside the capacitor is same everywhere.

correct option:3.a

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