A 0.060-kg tennis ball, moving with a speed of 5.16 m/s, has a head-on collision

Question

A 0.060-kg tennis ball, moving with a speed of 5.16 m/s, has a head-on collision with a 0.090-kg ball initially moving in the same direction at a speed of 3.74 m/s. Assume that the collision is perfectly elastic. Determine the speed of the 0.060-kg ball after the collision. Express your answer to two significant figures and include the appropriate units. ANSWER: upsilon_1 = 2.9 m/s Determine the direction of the velocity of the 0.060-kg ball after the collision. ANSWER: in the direction of the initial velocity in the direction opposite to the initial velocity Determine the speed of the 0.090-kg ball after the collision. Express your answer to two significant figures and include the appropriate units. ANSWER: upsilon_2 Determine the direction of the velocity of the 0.090-kg ball after the collision. ANSWER: in the direction of the initial velocity in the direction opposite to the initial velocity

Explanation / Answer

suppose after collision 0.06kg ball moves with v2 and 0.09 kg ball with v1 speed.

for elastic collision,

velocity of approach = velocity of separation

5.16 - 3.74 = v1 - v2

v1 = 1.42 + v2

Applying momentum conservation for collision,

0.06 x 5.16 + 0.09 x 3.74 = 0.06v2 + 0.09 v1

0.6462 = 0.06v2 + 0.1278 + 0.09v2

v2 = 3.46 m/s

v1 = 4.88 m/s

(A) 3.46 m/s

(b) in the direction of initial velocity

(c) 4.88 m/s

(d) in the direction of initial velocity

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.