A 0.018 kg marble sliding to the right at 26.8 cm/s on a frictionless surface ma

Question

A 0.018 kg marble sliding to the right at 26.8
cm/s on a frictionless surface makes an elastic
head-on collision with a 0.018 kg marble
moving to the left at 24.1 cm/s. After the
collision, the first marble moves to the left at
24.1 cm/s.

Part 1 of 3
Find the velocity of the second marble after
the collision.
Answer in units of m/s0.268

THE ANSWER TO PART 1 IS  0.268M/s IF THAT HELPS

NEED 2 AND 3 PLZ

(part 2 of 3)
What is the total kinetic energy before the
collision?

Answer in units of J

(part 3 of 3)
What is the total kinetic energy after the
collision?

Answer in units of J

Explanation / Answer

since there is no external force acting along horizontal direction
applying conservation of linear momentum along horizontal direction
we get
0.018*26.8 +0.018*(-24.1) = 0.018*(-24.1) + 0.018*v
we get v=26.8m/s
so velocity of second marble after collision is 26.8m/s towards right
(b)
total kinetic energy before collision is
(1/2)*0.018*0.2682 + (1/2)*0.018*0.2412 = 1.169145*10-3 J

(c)

total kinetic energy after collision is

(1/2)*0.018*0.2412 + (1/2)*0.018*0.2682 = 1.169145*10-3 J

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