Three boxes are placed on a seesaw. Box #1 (8 kg) ... Three boxes are placed on

Question

Three boxes are placed on a seesaw. Box #1 (8 kg) ... Three boxes are placed on a seesaw. Box #1 (8 kg) is placed at the very end of the left side of the 3.4 m long seesaw. Box #2 (13 kg) is placed at the other end of the seesaw. The pivot point of the seesaw is 0.2 m to the left of the middle of the seesaw. -

How far away from the pivot point would you need to place Box #3 (31 kg) for the seesaw to be balanced?

Would you need to place Box #3 to the left or right of the pivot for the seesaw to be balanced? Right

What is the net torque if Box #3 were placed at the pivot point?

The answers are not .41 m and 127 n/m

Explanation / Answer

pivot point at = 1.7 - 0.2 = 1.5 from left and 1.9 from right

8*1.5 + 31*x = 13*1.9

x = 0.4097 m from the pivot to the left = 0.41 m

Net torque = (13*1.9 - 8*1.5)*9.81 = 124.59 Nm

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