Two forces, of magnitudes F 1 = 100 N and F 2 = 20.0 N, act in opposite directio

Question

Two forces, of magnitudes F1 = 100 N and F2 = 20.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1) Initially, the center of the block is at position xi = -6.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm .

A)Find the work W1 done on the block by the force of magnitude F1 = 100 N as the block moves from xi = -6.00 cm to xf = 5.00 cm .

B)Find the work W2 done by the force of magnitude F2 = 20.0 N as the block moves from xi = -6.00 cm to xf = 5.00 cm .

C)What is the net work Wnet done on the block by the two forces?

D)Determine the changeKfKi in the kinetic energy of the block as it moves from xi = -6.00 cmto xf = 5.00 cm .

Confused about the above questions/problem. Any help appreciated, thank you!

Explanation / Answer

A) work done = F1 * displacement

= 100*(5-(-6))*0.01 = 11 N

B) F2* s * cos 180

= 20*(5+6)*0.01*-1

= -2.2 N

C)net work done = 11-2.2=8.8 N

D) change in kinetic energy = work done = 8.8 N

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