What must the charge (sign and magnitude) of a particle of mass 1.42 g be for it
ID: 1645043 • Letter: W
Question
What must the charge (sign and magnitude) of a particle of mass 1.42 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 600 N/C? Use 9.81 m/s^2 for the magnitude of the acceleration due to gravity. What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67 times 10^-27 kg for the mass of a proton, 1.60 times 10^-19 C for the magnitude of the charge on an electron, and 9.81 m/s^2 for the magnitude of the acceleration due to gravity.Explanation / Answer
A)
m = mass of the charge = 1.42 g = 1.42 x 10-3 kg
E = electric field = 600 N/C
q = magnitude of the charge
for the charge to be stationary , the electric force on the charge by the electric field must balance the weight of the charge
hence
qE = mg
q (600) = (1.42 x 10-3) (9.81)
q = 2.32 x 10-5 C
The electric force on the charge must be in upward direction to balance the weight in down direction
As we can see , electric force on the charge is upward while the electric field is downward. hence the charge experience electric force in opposite direction of electric field which is a characteristic of a negative charge.
hence charge is negative
B)
m = mass of the proton = 1.67 x 10-27 kg
q = charge on proton = 1.6 x 10-19 C
E = electric field = ?
for the charge to be stationary , the electric force on the charge by the electric field must balance the weight of the charge
hence
qE = mg
(1.6 x 10-19 ) E = (1.67 x 10-27) (9.81)
E = 1.02 x 10-7 N/C
The electric force on the charge must be in upward direction to balance the weight in down direction
As we can see , electric force on the charge is upward and the charge on proton is positive. hence the charge experience electric force in same direction of electric field which is a characteristic of a positive charge.
hence electric field is upward.
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