A basketball is released from rest on a 15 degree incline. What is the angular a

Question

A basketball is released from rest on a 15 degree incline. What is the angular acceleration of the ball? Assume that the ball rolls without slipping and the basketball is a thin spherical shell with diameter 23 cm. (the moment of inertial of a thin spherical shell about its center of mass is l_cm = 2mR^2/3) An ideal spring is used to fire a 15.0 g pellet horizontally. The spring has a spring constant of 20 N/m and is initially compressed by 7.0 cm. find the kinetic energy of the pellet as it leaves the spring.

Explanation / Answer

Question 6) Using conservation of energy

mv^2/2 = kx^2/2

Given m = 0.015 kg , k = 20N/m , x = 0.07 m

Let v be the velocity of the pellet while leaving

v = (kx^2/m)

v = (20*0.07^2/0.015)

v = 2.556 m/s

So the kinetic energy = mv^2/2

Kinetic energy = 0.015*2.556^2/2 = 0.049 J

Therefore, kinetic energy = 0.049 joules

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