Question
GRE Practice Test&Review; com/ibiscrs/mod/ibis/view.php?id=3653748 0 Not Set 73 8/1007/9/2017 08:52 PM Print il Calculator Periodic Table Question 1 of 13 Sapling Learning A partidle that carries a net charge of -238 jC is held in a region of constant, uniform electric field. The electric field vector is oriented 25.2e clockwise from the vertical axis, as shown. If the magnitude of the electric field is 9.32 N/C how much work is done by the electric field as the particle is made to move a distance of d = 0.956 m straight up? Number 25.2 1.92 × 10-4 What is the potential difference between the particle's initial and final positions ( -vo? Number -2.0× 10-4 Exit- 'Q Previous Give Up & View Solution 9 Check Answer O Next Hint
Explanation / Answer
Component of electric field Ecos 25.2=9.32×cos25.2=8.43N/C
V=E×l=8.43×0.956=8.1V
Work done=qV= 8.1×23.8×10^-6=191.87×10^-6J
