Four circular loops of wire are suspended from non-conducting cords so that they
ID: 1648811 • Letter: F
Question
Four circular loops of wire are suspended from non-conducting cords so that they hang in a un harmonic magnetic field, as shown. The loop on the left swings back and forth like a pendulum in simple harmonic motion (SHM), in and out of the magnetic field. The second loop (from left) swings like a pendulum, but remains immersed in the region of constant B-field. The third loop oscillates up and down in SHM and stays in the field. The loop on the right rotates on the string in a fixed direction without moving the string, and always within the B-field. In which of the loops is there an induced current? A) None of the loops have a current induced in them. B) Only Loop 1. C) Only Loop 4. D) Loops 1 and 2. E) Loops 2 and 3. F) Loops 1 and 4. G) All of the loops have a current induced in them. A beam consisting of five types of ions labeled A, B, C, D, and E enters a region that contains a uniform magnetic field as shown in the figure below. The field is perpendicular to the plane of the paper, but its precise direction is not given. All ions in the beam travel with the same speed. The table below gives the masses and charges of the ions. Circle the letter of the ion that falls at position 2.Explanation / Answer
26) emf will be induced in loop 1 and 4 because there will be change in flux in both cases, in case 1 when pendulum will be out of the region then flux passing through it will be zero and in case of 4 if plane of loop is parallel to magnetic field then flux passing through it will be zero so flux will be changing in case of 1 and 4 only. so emf will also be induced in case of 1 and 4 only
so option D is correct.
27) since ion C is having greatest mass and so it will be having largest radius so indeed ion C is reaching to position 1 and since its positively change and getting deflected towards left so indeed magnetic field is perpendicularly into the plane of paper so particle reaching at position 2 must have positive charge and mass shouldn't be minimum so definitely it will be ion B.
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