A scuba tank, when fully submerged, displaces 15.5 L of seawater. The tank itsel

Question

A scuba tank, when fully submerged, displaces 15.5 L of seawater. The tank itself has a mass of 12.2 kg and, when "full, " contains 4.94 kg of air. Assuming only a weight and buoyant force act, determine the net force (magnitude) on the fully submerged tank at the beginning of a dive (when it is full of air). Express your answer with the appropriate units. Assuming only a weight and buoyant force act, determine the net force (direction) on the fully submerged tank at the end of a dive (when it no longer contains any air). upward downward no direction Assuming only a weight and buoyant force act, determine the net force (magnitude on the fully submerged tank at the end of a dive (when it no longer contains any air). Express your answer with the appropriate units.

Explanation / Answer

The buoyant force is the weight of the water it displaces

Density = mass/Volume so Volume*Density = mass and weight = g*Volume*Density

We have to convert liters to m³

One of the nicest things about MKS is 1ml = 1cc = 1cm³

15.5L*1000cm³/L * (1m/100cm)³ = 0.0155m³

Weight of water displaced = 9.81*0.0155*1025 = 155.86N (assuming density as 1025)

The weight of the tank = (12.2+4.94)*9.81 = 168.14N

168.14-155.86 = 12.28N <---- B

The weight of the tank without air = 12.2*9.81 = 119.68N

155.86-119.68 = 36.18N <------ D

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