A scuba tank, when fully charged, has a pressure of 194 a t m at 20 ? C . The vo

Question

A scuba tank, when fully charged, has a pressure of 194atm  at 20 ?C. The volume of the tank is 11.3L .

I've answered parts A and B. I Included them so you could get the context and I think they're necessary to complete C. Please help!

A ) What would the volume of the air be at 1.00 atm and at the same temperature? 2190 L.

B) Before entering the water, a person consumes 2.0 L of air in each breath, and breathes 12 times a minute. At this rate, how long would the tank last? t= 91 minutes

C) At a depth of 12.3m  of sea water and temperature of 11?C, how long would the same tank last assuming the breathing rate does not change?         

Explanation / Answer

A)

We know that
PV/T = constant
V2 = V1 * P1/P2
   = 194 * 11.3 L
   = 2192.2 L
  
B)
Time :

= 2192.2 / (2*12)

= 91.34 min


C)
Pressure at 12.3 m depth :

= [1+ {(12.3*1000*9.8)/(10^5)}] atm

= 2.21 atm

Volume of air for breathing :

= (2192.2/2.21)

= 991.95 L

Required time :

= 91.34/2.21

= 41.33 min

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