I need help with 13,14 , 15, 16 in 20 mins and thank you a RcL series eircuit wi

Question

I need help with 13,14 , 15, 16 in 20 mins and thank you

a RcL series eircuit with f-60 He, R-600 ac-9,F, and L. - 6 H. Find the impedance of the circuit, 2 A) 2160 B) 2060 C) 666.70 D) 7200 ohrn E) 3600 14. A kiven individusl is unable to ase cajects ee whposer hse o em 5. If anglemode 50 when Tua1.2, and o1.6, ad nleh 6. For a diverging lens with one flat surface, the radius of curvature for the curved surface is 13.5 cm. What mast this problem? A) 17.825243D B) 14.117647 D C)-3312D (Dy -L,111 Diopsers E) -0.383 D A) 25 B) 41.67° C) 45.962666' D) 35.1° E) 36° the index of refraction be so that the focal length is-15 cm? A) 2.6325 B) 1.51084 C) 1.2376 D) 2.3 E) 1.9 7. A Two point sources (pixels) of monochromatic radiation can be resolved as close as 1.1 cm apart when viewis them at a distance of 1800 m through a lens 3 cm in diameter. What is the wavelength of the radiation? A) 9.9 X 10'm B) 33X 107m C) 1503 X 10? m D) 5.94 X 107m E) 6.6x10'm

Explanation / Answer

13) f = 60 Hz

R = 600

XL = 2fL = 2260.8

Xc = 1/(2fc) = 294.88

Impedance = [R2 + (XL-XC)2] = 2055.42

Therefore, option (B) is the correct answer

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14) focal length of required lens = 90 cm = 0.9 m

Power = 1/(focal length in metres) = 1/0.9 = 1.11 D

Therefore, option (D) is the correct answer

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15) snell's law states that n*sin() = constant

1.2*sin(50) = 1.6 *sin() where = anglerefracted

=> = 35.07 degrees

Therefore, option (D) is the correct answer

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16) (1/f) = (n-1)(1/R)

=> n = 1 + (R/f)

=> n = 1 + (13.5/15) = 1.9

Therefore, option (E) is the correct answer

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