A candle is 49 0 cm in front of a convex spherical mirror of radius of curvature

Question

A candle is 49 0 cm in front of a convex spherical mirror of radius of curvature 700 cm. What are the image distance and the magnification respectively? -20.4 cm, +0 417 +20.4 cm, -0.417 +1 22.5 cm, +2.50 0.20 4 cm, -0417 Two waves of same wavelength and frequency, with a phase angle of zero are said to be "_____". If you triple the force through the same distance, how much work would you do? 1/3 the work the work The same amount of work 3 times the amount of work What is the maximum value of the electric field E at 1 0 m from a 100W light bulb radiating in all directions?(mu_0 = 4pi times 10^-7 T-mA, e = 3.00 times 10^8 m/s) 77 V/m 2000 V/m 4000 V/m 6000 V/m

Explanation / Answer

26) o = 49 cm ; R = -70 cm =. f = -35 cm ;

from lens eqn,

1/f = 1/i + 1/o

1/i = 1/-35 - 1/49 => i = -20.4 cm

magnification is, M = -i/o = -(-20.4)/49 = +0.417

Hence, correct answer is : -20.4 cm and +0.417

27) in phase

28)We know that work and force are related as:

W = F x d

where, W is work, F is force and d is the distance

W1 = F x d

W2 = 3F x d

W1/W2 = Fd/3Fd = 1/3

W2 = 3W1

Correct ans: 3 times the amount of work.

29)we know that,

I = P/A ; I isintensity, P is power and A is area

also I = Emax^2/2 u0 c

equating the two and solving for Emax we get

Emax = sqrt (2 u0 c P/ A)

E(max) = sqrt (2 x 4 pi x 10^-7 x 3 x 10^8 x 100/ 4 pi 1^2) = 77 V/m

Hence, Emax = 77 V/m is the correct answer.

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