In the figure, two identical springs have unstretched lengths of 0.25 m and spri

Question

In the figure, two identical springs have unstretched lengths of 0.25 m and spring constants of 300 N/m. The springs are attached to a small cube and stretched to a length L of 0.36 m as in Figure A. An external force P pulls the cube a distance D = 0.020 m to the right and holds it there. (See Figure B.) A) The external force P, that holds the cube in place in Figure B, is closest to a)14 N. b) 24 N. c) 21 N. d) 18 N. e) 12 N. P = F1 - F2 - k (x1 - x2) = k(0.11 + 02 - 0.11 + 0.02) = 2*0.02*300 = 12N B) The work done by the external force P in pulling the cube 0.020 m is closest to

Explanation / Answer

Given that

distance x1=0.11+0.02=0.13 m

distance X2=0.11-0.02=0.099 m

spring constant k=300 N/m

now we find the work done

work done W=1/2k(x1+x2)^2=1/2*300*(0.13+0.099)^2=7.87 J

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