A tiny ball (mass = 1.5 g) carries a charge of -20 nC. What is the electric fiel

Question

A tiny ball (mass = 1.5 g) carries a charge of -20 nC. What is the electric field that would cause the ball to float above the ground? State the direction of this electric field. At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 270 N/C. At a distance r2 from the charge, the field has a magnitude of 90 N/C. What is the value of r2/r1? Two charges are placed on the x axis. One of the charges (q1 = +2.2 C) is at x1 = +4.0 cm and the other (q2 = -6 C) is at x2 = +8.0 cm. Find the net electric field (magnitude and direction, with direction indicated by sign) at (a) x = 2 cm (b) x = +6.0 cm.

Explanation / Answer

According to the chegg guidelines I am allowed to answer only 1 question at a time.

1) m = 1.50 * 10 ^ -3 kg Q = -20 nC

E= mg / Q = 1.50 * 10 ^ -3 * 9.81 / 20 *10^-9

E= 735000 N/c direction = downwards ==================ANSWER)

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