An electron moves horizontally (in the positive x direction)perpendicular to a c

Question

An electron moves horizontally (in the positive x direction)perpendicular to a constant magnetic field oriented so as todeflect the electron upward. What is the direction of thisfield? The magnitude of the field is 0.008 T.
What is the speed of the electron if the magnetic force justcancels the gravitational force on the electron, leaving it inhorizontal flight?
How would the magnetic field have to be changed so that forthe same velocity a proton would also traverse a horizontalpath?
What is the speed of the electron if the magnetic force justcancels the gravitational force on the electron, leaving it inhorizontal flight?
How would the magnetic field have to be changed so that forthe same velocity a proton would also traverse a horizontalpath?

Explanation / Answer

According to lorentz ' equation about the force. We can indicate that the magnetic field 's direction is in the ynegative axis. The magnetic field is equal to gravity force so Bqv=mg v=mg/Bq=9,1^10-31*9,8/(0,008*1,6*10^-19)=7*10^-9(m/s) If it is the proton so The magnetic field have to reverse so ithead toward positive y axis. B=mg/qv=14,6(T)

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