An electron is released from rest in between two oppositely charged parallel con

Question

An electron is released from rest in between two oppositely charged parallel conducting plates. If it takes the electrons to travel a distance of 1.7 cm, what is the surface charge density of each plate? A.8.57*10^-13 C/m^3 B.3.14*10^-19 C/m^3 C.1.71*10-12 C/m^3 D.3.42*10^-13 C/m^3 E.3.42*10^-12 C/m^3
An electron is released from rest in between two oppositely charged parallel conducting plates. If it takes the electrons to travel a distance of 1.7 cm, what is the surface charge density of each plate? A.8.57*10^-13 C/m^3 B.3.14*10^-19 C/m^3 C.1.71*10-12 C/m^3 D.3.42*10^-13 C/m^3 E.3.42*10^-12 C/m^3
An electron is released from rest in between two oppositely charged parallel conducting plates. If it takes the electrons to travel a distance of 1.7 cm, what is the surface charge density of each plate? A.8.57*10^-13 C/m^3 B.3.14*10^-19 C/m^3 C.1.71*10-12 C/m^3 D.3.42*10^-13 C/m^3 E.3.42*10^-12 C/m^3

Explanation / Answer

10^-6 sec to travel 1.7 cm strating from rest:

d = v0 t + a t^2 /2

0.017 = 0 + a(10^-6)^2/ 2

a = 3.4 x 10^10 m/s^2

a = q E / m

3.4 x 10^10 = (1.602 x 10^-19)(E) / (9.109 x 10^-31)

E = 0.1936 N/C

and E = sigma/ e0

sigma = e0 E = 1.71 x 10^-12 C/m^2

Ans(C)

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