An electron is placed on the x axis at x = L. A proton is placed on the y axis a

Question

An electron is placed on the x axis at x = L. A proton is placed on the y axis at y = L.

a.) Calculation Determine the force (a vector) exerted on the proton.

b.) Calculation Determine the electric potential energy of the electron.

c.) Conceptual What direction is the net electric field due to the two charges at the origin (x = 0, y = 0). Explain. (Please explain the physics to support your answer.)

d.) Calculation Determine the net electric potential due to the two charges at the origin (x = 0, y = 0).

e.) Calculation Determine the net electric field due to the two charges at a point on the x axis at x = L.

Explanation / Answer

a) F = kq1q2/r^2

= kq^2/(sqrt2 L)^2

= kq^2/(2L^2)

b)E = kq1q2/r

= -kq^2/(sqrt2 L)

c) direction is at 225 degree with +x axis....because both proton will create electric field towards -y axis and electron will create electric field in -x direction

d)V = kq1/L + kq2/L

= kq/L - kq/L = 0

e) E = [- kq/(2L)^2 ] i + [kq/(2L^2) ] (i-j)/sqrt2

= kq/L^2 [-0.25i+0.354i -0.354j]

= 0.369  kq/L^2

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