(a) Two 63 g ice cubes aredropped into 260 g of water in athermally insulated co
ID: 1665886 • Letter: #
Question
(a) Two 63 g ice cubes aredropped into 260 g of water in athermally insulated container. If the water is initially at25°C, and the ice comes directly from a freezer at -15°C,what is the final temperature at thermal equilibtrium? (Neglect theheat capacity of the glass.)°C
(b) What is the final temperature if only one ice cube isused?
°C
Explanation / Answer
Assume that the final temperature is larger than zero. Specific heat capacity water - 4.187 kJ/kgK Specific heat capacity ice - 2.108 kJ/kgK So 63g*2*2108J/kgK*15 = 3984 is the heat needed to bring two cubesfrom -15C to 0C 260g*4200*25=27300 J is the heat of the water need to pull out tolowered its temperature to 0c The heat needed for 2 cubes to change to water63g*2*334kJ/kg=42084>27300 so the final temperature is zero. b), the heat needed for ice now is halve Q1=1992 J, Q2=21042. J 27300>Q1+Q2 so the final temperature is bigger than zero. let the temperature be T T*(63+270)g*4200J/kgK=27300-1992-21042=3C
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