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(a) Two 55 g ice cubes are dropped into 260 g of water in a thermally insulated

ID: 2160148 • Letter: #

Question

(a) Two 55 g ice cubes are dropped into 260 g of water in a thermally insulated container. If the water is initially at 27

Explanation / Answer

a)Let final temperature be T. Then Heat gained by ice cubes = Heat lost by water. =>(2*0.055*2220*(0-10)) + (2*0.055*333) + (2*0.055*4186*(T-0)) = (0.26*4186*(27-T)) =>2478.63 + 460.46T = -1088.36T + 29385.72 =>(460.46+1088.36)T = 29385.72 - 2478.63 =>T = 17.37264 oC b)Let final temperature be T. Then Heat gained by ice cubes = Heat lost by water. =>(0.055*2220*(0-10)) + (0.055*333) + (0.055*4186*(T-0)) = (0.26*4186*(27-T)) =>1239.315 + 230.23T = -1088.36T + 29385.72 =>(230.23+1088.36)T = 29385.72 - 1239.315 =>T = 21.34583 oC