A block of weight mg sits on an inclined plane as shown. (Intro 1 figure1) A for

Question

A block of weight mg sits on an inclined plane as shown. (Intro 1 figure1) A force of magnitude F is applied to pull the block up the incline at constant speed. The coefficient of kinetic friction between the plane and the block is mu. What is the total work Wfric done on the block by the force of friction as the block moves a distance L up the incline? Express the work done by friction in terms of any or all of the variables mu, m, g, theta, L, and F. What is the total work WF done on the block by the applied force F rightarrow as the block moves a distance L up the incline? Express your answer in terms of any or all of the variables mu, m, g, theta, L, and F. Now the applied force is changed so that instead of pulling the block up the incline, the force pulls the block down the incline at a constant speed. (Intro 2 figure1) What is the total work Wfric done on the block by the force of friction as the block moves a distance L down the incline? Express your answer in terms of any or all of the variables mu, m, g, theta, L, and F. What is the total work WF done on the box by the appled force in this case? Express your answer in terms of any or all of the variables mu, m, g, theta, L, and F.

Explanation / Answer

When the block moving downwards         Wfr= -*mgcos*L The work done by the applied force     W = F*L The net work done on the block is    W = [ F + mgsin -*mgcos ]L

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