Two moles of a diatomic ideal gas has initial volume of 1L andtemperature of 300

Question

Two moles of a diatomic ideal gas has initial volume of 1L andtemperature of 300K. Frist Gas expands adiabatically to 3 times theintial volume. Then it is expanded isobarically to a new volume andcompressed istothemally back to its original state. 1- how much heat is added during the isobaric process? Two moles of a diatomic ideal gas has initial volume of 1L andtemperature of 300K. Frist Gas expands adiabatically to 3 times theintial volume. Then it is expanded isobarically to a new volume andcompressed istothemally back to its original state. 1- how much heat is added during the isobaric process?

Explanation / Answer

n = 2 mole, V1 = 1 L, T1 = 300 K, =1.40, pressure P1 = nRT1/V1 after abiabatic process, V2 = 3V1,P2 =P1(V1/V2) =P1*(1/3), T2 =P2V2/(nR) = 3*(1/3)T1 after isobaric process, P3 = P2, volumeV3, temperature T3 = T1, after isothermal process, temperature = T1, volume =V1, pressure = P1 P1V1 = P3V3 V1/V3 = P3/P1 =P2/P1 = (1/3), V3 = 3*V1 work done during the isobaric process = P2(V3 - V2) =P3V3 - P2V2 =nRT1 - P1(1/3)*3V1 = nRT1 (1 -31-) = 1773 J

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