A 50 kg block of ice slides downa frictionless incline 1.5 m long and 0.89 m hig

Question

A 50 kg block of ice slides downa frictionless incline 1.5 m long and 0.89 m high. A worker pushes up against the ice,parallel to the incline, so that the block slides down at constantspeed. (a) Find the magnitude of the worker's force.
N How much work is done on the block by the following forces? (b) the worker's force
J

(c) the gravitational force on the block
J

(d) the normal force on the block from the surface of theincline
J

(e) the net force on the block
J (a) Find the magnitude of the worker's force.
N (b) the worker's force
J

(c) the gravitational force on the block
J

(d) the normal force on the block from the surface of theincline
J

(e) the net force on the block
J

Explanation / Answer

a, The incline angle sin = 0.89/1.5 => = 36.4o The force made by the worker equal to the gravitational forceon the direction of the plane: F = mg sin = 296.7 N b, The work done by the worker is W1 = -F l =-445J c, The work done by the gravity is W2 = mgsin l = 445J d, The normal force perpendicular to the motion, hence make nowork ==> work done is zero e, The velocity is constant so the net force on the block iszero, hence no work done by this net force The force made by the worker equal to the gravitational forceon the direction of the plane: F = mg sin = 296.7 N b, The work done by the worker is W1 = -F l =-445J c, The work done by the gravity is W2 = mgsin l = 445J d, The normal force perpendicular to the motion, hence make nowork ==> work done is zero e, The velocity is constant so the net force on the block iszero, hence no work done by this net force

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