Q: A bungee jumper falls for 1.3 s before the bungee cordbegins to stretch. Unti

Question

Q: A bungee jumper falls for 1.3 s before the bungee cordbegins to stretch. Until the jumper has bounced back up to thislevel, the bungee causes the jumper to have an average accelerationupward of 4 m/s2. a) How fast is the jumper going when the bungee cord begins tostretch? b) How far below the diving platform is the jumper at thatmoment? c) How long after the bungee cord begins to stretch does thejumper reach the low point of the drop? d) How far below the diving platform is the jumper t theinstant the speed is zero? Q: A bungee jumper falls for 1.3 s before the bungee cordbegins to stretch. Until the jumper has bounced back up to thislevel, the bungee causes the jumper to have an average accelerationupward of 4 m/s2. a) How fast is the jumper going when the bungee cord begins tostretch? b) How far below the diving platform is the jumper at thatmoment? c) How long after the bungee cord begins to stretch does thejumper reach the low point of the drop? d) How far below the diving platform is the jumper t theinstant the speed is zero?

Explanation / Answer

Before the bungee cord begin to stretch, only gravity force act onthe jumper. so v=g*t=12,74(m/s) b.We have h=g*t^2/2=8,3m c. Let the time be t we have v=v0-at v=0 so v0=at so t=v0/a=12,74/4=3,2s d. Let h be the increase in distance of the jumper. h=v0t-at^2/2=t*(v0-at/2)=t*v0/2 h=20,4(m). so H=h+h=28,7m

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