A block of mass m 1 = 3.6 kg rests on a frictionless horizontal surface. Asecond

Question

A block of mass m1 = 3.6 kg rests on a frictionless horizontal surface. Asecond block of mass m2 = 1.8 kg hangs from an ideal cord of negligible massthat runs over an ideal pulley and then is connected to the firstblock. The blocks are released from rest. ____m/s (a) What is the velocity of the first block 1.8 s after the release of the blocks, assuming thefirst block does not run out of room on the table and the secondblock does not land on the floor? (b) How far has block 1 moved during the 1.8-s interval? ___m
(c) What is the displacement of the blocks from their initialpositions 0.30 s after they arereleased?    block 1magnitude ____m    block 2 magnitude ____m A block of mass m1 = 3.6 kg rests on a frictionless horizontal surface. Asecond block of mass m2 = 1.8 kg hangs from an ideal cord of negligible massthat runs over an ideal pulley and then is connected to the firstblock. The blocks are released from rest. ____m/s (a) What is the velocity of the first block 1.8 s after the release of the blocks, assuming thefirst block does not run out of room on the table and the secondblock does not land on the floor? (b) How far has block 1 moved during the 1.8-s interval? ___m
(c) What is the displacement of the blocks from their initialpositions 0.30 s after they arereleased?    block 1magnitude ____m    block 2 magnitude ____m

Explanation / Answer

Simplifying everything
Acc = 1.8*9.8 / ( 3.6 + 1.8)
a = 3.267 m/s/s

Veloctiy
V = vo + at
V = 0 + (3.267m/s/s)*1.8s
V = 5.88 m/s X = v0^2 + 1/2at^2
X = 0 1/2*3.267m/s/s* (1.8s^2) X = 5.29m

block 1 x = 0 +1/2(3.267m/s/s*(.30s^2) x = + .147m (x dimension)right(across) is positive.

y = 0 + 1/2(3.267m/s/s*.30s^2
y = -.147m. Down

Please RATE!

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