A block of mass M slides down a plane at an angle of 37 o to the horizontal. The

Question

A block of mass M slides down a plane at an angle of 37o to the horizontal. The coefficient of kinetic friction = 0.20. The horizontal lines in the picture represent magnitude of forces, in units of the force of gravity on the block. The arrows show directions for forces. DATA: sin(37o)=0.60 cos(37o)=0.80, tan(37o)=0.75.

Enter two 2-letter combinations, for the components of the force of gravity on the block (1) along the incline and (2) perpendicular to the incline. Format the answer with no spaces and a comma. Example: JD,PR


Enter the 2-letter combination for the total force on the block.

Explanation / Answer

(1) along the incline
Mgsin37 = 0.6Mg
CL
(2) perpendicular to the incline
Mgcos37 = 0.8 Mg
IM
so answer to first part is CL,IM

total force is along the incline
Mgsin37 - Mgcos37 = 0.6Mg - 0.2*0.8Mg = 0.44Mg

2-letter is GL

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