A block of mass 589 g is pushed against the spring (located on the left-hand sid

Question

A block of mass 589 g is pushed against the spring (located on the left-hand side of the track) and compresses the spring a distance 5.4 cm from its equilibrium position(as shown in the ?gure below). The block starts from rest, is accelerated by the compressed spring, and slides across a frictionless horizontal track (as shown in the ?gure below). It leaves the track horizontally, ?ies through the air, and subsequently strikes the ground. The acceleration of gravity is 9.81 m/s2 What is the spring constant? Answer in units of N/m

part 2

What is the speed v of the block when it leaves the track? Answer in units of m/s

part 3

What is the total speed of the block when it hits the ground? Answer in units of m/s

Explanation / Answer

part 1:

The force, F, on the spring is m*g = 0.589 * 9.81 = 5.778 N

So, remembering to convert cm to m

k = 5.778/0.054 = 107 N/m

part 2:

Time of flight T= sq rt (2h/g)

Horizontal velocity v= range / time of flight

part 3:

V= sq rt [v^2 +2gh]

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