A block of mass 2.50 kg is pushed 2.80 malong a frictionless horizontal table by

Question

A block of mass 2.50 kg is pushed 2.80 malong a frictionless horizontal table by a constant 14.0 N force directed 25.0° below the horizontal. (a) Determine the work done by the appliedforce.
1 J

(b) Determine the work done by the normal force exerted by thetable.
2 J

(c) Determine the work done by the force of gravity.
3 J

(d) Determine the work done by the net force on the block.
4 J (a) Determine the work done by the appliedforce.
1 J

(b) Determine the work done by the normal force exerted by thetable.
2 J

(c) Determine the work done by the force of gravity.
3 J

(d) Determine the work done by the net force on the block.
4 J

Explanation / Answer

   we are given with    mass of the block M = 2.50 kg    displacement of the block s = 2.80 m    force F = 14.0 N    angle = 25o    acceleration due to gravity g = 9.80 m /s2       if M g is the weight of the block and R is thereaction force then (a)    the work done by the applied force will be    W = F cos s        = ...... J (b)    the work done by normal force exerted by thetable will be        W = R s cos90o    but we can see that the force and thedisplacement are perpendicular to each other the work    done will be zero    W = 0 J (c)    work done by the force of gravity is    W = M g s cos90o    but we can see that displacement andthe weight of the block are perpendicular to each other the    workdone will be zero    so we get    W = 0 J (d)    the work done by the net force on the block is Win part (a)    but we can see that displacement andthe weight of the block are perpendicular to each other the    workdone will be zero    so we get    W = 0 J (d)    the work done by the net force on the block is Win part (a)

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