A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table b
ID: 1724362 • Letter: A
Question
A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table by aconstant 16.0 N force directed 25.0°below the horizontal. (a) Determine the work done by the appliedforce.1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J
A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table by aconstant 16.0 N force directed 25.0°below the horizontal. (a) Determine the work done by the appliedforce.
1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J
(a) Determine the work done by the appliedforce.
1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J
Explanation / Answer
we are given with
mass of the block M = 2.50 kg
displacement of the block s = 2.60 m
force F = 16.0 N
angle = 25o
acceleration due to gravity g = 9.80 m /s2
if M g is the weight of the block and R is thereaction force then
(a)
the work done by the applied force will be
W = F cos s
= ...... J
(b)
the work done by normal force exerted by thetable will be
W = R s cos90o
but we can see that the force and the displacement areperpendicular to each other the work
done will be zero
W = 0 J
(c)
work done by the force of gravity is
W = M g s cos90o
but we can see that displacement and the weightof the block are perpendicular to each other the
workdone will be zero
so we get
W = 0 J
(d)
the work done by the net force on the block is W inpart (a)
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