In an amusement park ride, cars are suspended from L =4.25 m cables attached to

Question

In an amusement park ride, cars are suspended from L =4.25 m cables attached to rotatingarms at a distance of D = 6.21 m fromthe axis of rotation. The cables swing out at an angle of = 55° when the ride is operating. Whatis the angular speed of rotation?
Please write out the answer without any mews or w's or any of thatpoop! Just good old english! Thanks so much! Mike
D = 6.21 m fromthe axis of rotation. The cables swing out at an angle of = 55° when the ride is operating. Whatis the angular speed of rotation?
Please write out the answer without any mews or w's or any of thatpoop! Just good old english! Thanks so much! Mike

Explanation / Answer

We have T cos = mg Tsin = mv2/r ==> tan = v2 / rg Here r = 6.21 + 4.25sin55 = 7.029 m           v =r Therefore we have            tan55 = 2 r / g      ==> = g tan55 / r                 = 9.8 * tan55 / 7.029                 = 1.411 rad /s

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