Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magnitud

Question

Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magnitude 0.47T. When viewed edge-on, the firstsurface is tilted at an angle of 12 degrees from the horizontal,and a net magnetic flux of 8.4E-3 WB passes through it. The samenet magnetic flux passes through the second surface.(a) Determine the area of the first surface.(b) Find the smallest possible value of the are ofthe second surface. I'm not sure where to begin. Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magnitude 0.47T. When viewed edge-on, the firstsurface is tilted at an angle of 12 degrees from the horizontal,and a net magnetic flux of 8.4E-3 WB passes through it. The samenet magnetic flux passes through the second surface.(a) Determine the area of the first surface.(b) Find the smallest possible value of the are ofthe second surface. I'm not sure where to begin.

Explanation / Answer

(a) flux = B A sin .       0.0084 = 0.47 * A *sin12 .               A = 0.08596m2 =   859.6cm2     is the area of the firstsurface . (b) the second surface will have the smallest area if theangle is 90 degrees... i.e. if the surface is vertical so that themag field passes straight through it. Then... .          0.0084 = 0.47* A * sin90 .            A =  0.01787 m2 =   178.7cm2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.