Q) Assuming that the screen is sufficientlybright, at what distance can you no l

Question

Q) Assuming that the screen is sufficientlybright, at what distance can you no longer resolve two pixels ondiagonally opposite corners of the screen, so that the entirescreen looks like a single spot? Note that the size (0.360 meters)quoted for a monitor is the length of the diagonal. Assuming that the screen is sufficientlybright, at what distance can you no longer resolve two pixels ondiagonally opposite corners of the screen, so that the entirescreen looks like a single spot? Note that the size (0.360 meters)quoted for a monitor is the length of the diagonal.

Explanation / Answer

Figure about 0.7 arc minute for the resolution of the humaneye: http://www.clarkvision.com/imagedetail/e… one arc minute is about 291 micro-radians: http://en.wikipedia.org/wiki/Arcsecond So using arc length = R x central angle, we have: 0.360 = R x (0.7)(291)(10^-6) = R x 2 x 10^-4 so R = 0.360 / (2 x 10^-4) = 0.18 x 10^4 = 1800 You can argue about a factor of 2 (one cycle vs 3/2 cycle, etc.)but this should be the right order of magnitude. For Rayleigh criteria: @ = wavelength / diameter for wave length = 550 x 10^-9 and diameter = 3.1 x 10^-3 this gives @ = 177.4 x 10^-6 radians

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