9) A converging lens has a focal length of 19.3 cm. Give the image distance and
ID: 1678810 • Letter: 9
Question
9) A converging lens has a focal length of 19.3 cm. Give the image distance and magnification forthe following object distances, using the correct sign conventions.Select all options that correctly describe the image. If the imageis located at infinity, enter "infinity" for the image distance andfor the magnification, and select "no image is formed". (a) object distance = 10.7cmimage distance cm
magnification
X
side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted 9) A converging lens has a focal length of 19.3 cm. Give the image distance and magnification forthe following object distances, using the correct sign conventions.Select all options that correctly describe the image. If the imageis located at infinity, enter "infinity" for the image distance andfor the magnification, and select "no image is formed". (a) object distance = 10.7cm
image distance cm
magnification
X
side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted
Explanation / Answer
Given focal length of the cnverging lens f = 19.3 cm object distance do = 10.7 cm Thin lens equation is 1 / do + 1 / d i = 1 /f 1 / 10.7 + 1 /di = 1 / 19.3 1 / d i = 1 /19.3 - 1 /10.7 cm image distance d i = -24cm the image is formed same side to theobject So the image is virtual image Magnification M = - di / d o = - ( - 24 ) / 39.2 =2.24 the image is uprighted withrespective to the objectRelated Questions
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