A 50.0 kg skater is traveling due east at a speed of 3.00 m/s. A70.0 kg skater i

Question

A 50.0 kg skater is traveling due east at a speed of 3.00 m/s. A70.0 kg skater is
moving due south at a speed of 7.00 m/s. They collide and hold onto each other after
the collision, managing to move off at an angle south ofeast, with a speed of Vf.
Assume that friction can be ignored.
(a) Find the angle .
(b) Find the speed Vf .

Explanation / Answer

According to conservation of momentum we have alongx-direction           m1 u1 = M Vfcos Along the vertical direction           m2 u2 = M Vfsin ==> m2 u2 / m1 u1 = tan ==> tan = 7 * 7 / 5 * 3                = 3.2666 ==> = 72.97o Therefore           Vf = m 1 u1/ M cos               = 5 * 3 / 12 * cos72.97               = 4.27 m/s

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