Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

GENETICS Please Help! The answers have been provided under the questions but I r

ID: 168047 • Letter: G

Question

GENETICS Please Help! The answers have been provided under the questions but I really need to see the work/explanation for each as I do not understand. Thank you very much!!

89. Which are the recombinant classes in these three crosses?   
Answer: CD and cd, CE and ce, DE and de

90. Give the genotypes of the dihybrids in these three crosses, showing linkage arrangements.   
Answer: Cd/cD, Ce/cE, and De/dD.

91. Draw the map for these three genes, indicating the order and the lengths of the intervals in map units.   
Answer: CED; C-E = 10 m.u., D-E = 40 m.u., C-D = 44 m.u.

Dihybrid test crosses are made between each pairwise combination of the three genes C, D, and E with CD 222 CE 48 DE 198 Ce 455 Cd 280 De 289 CE 445 E 311 CD 280 cd 218 ce 52 de 202 1000 1000 1000 the following results:

Explanation / Answer

Answer:

89).

1. First cross recombinants: Cd and cD

2. Second cross recombinants: CE and ce

3. Third cross recombinants: DE and de

90).

1. First cross dihybrid: CD/cd

2. Second cross dihybrid: Ce/cE

3. Third cross dihybrid: De/dE

91).

Recombinaiton frequency = Distance between the genes

Recombination frequency = (no of recombinant/Total progeny)*100           

1). First cross RF = (498/1000)100 = 49.8%.

The distance between C & D is 49.8 map units

2). Second cross RF = (100/1000)100 = 10%.

The distance between C & E is 10 map units

3). Third cross RF = (400/1000)100 = 40%.

The distance between D & E is 40 map units