GENETICS Please Help! The answers have been provided under the questions but I r
ID: 168049 • Letter: G
Question
GENETICS Please Help! The answers have been provided under the questions but I really need to see the work/explanation for each as I do not understand. Thank you very much!!
94. What is the genotype of the females that gave rise to these progeny?
px sp cn+/px+ sp+ cn
95. Using the two point cross method, what are the distances between these three genes?
px-sp = .2 m.u., px-cn = 30 m.u., cn-sp = 30.2 m.u.
96. Using the three point cross method, determine which gene is in the middle (which has to be flipped).
px.
Explanation / Answer
Answer:
94). px sp +/ + + cn
95).
sp-px = 0.21 mu
px-cn = 30.06 mu
sp-cn= 30.2 mu
96). The middle gene is px
Explanation:
Imagine the order is px sp + / + + cn
1. If single cross over (SCO) occurs between px & sp
Normal order= px --------- sp & + ----- +
After cross over= px-----+ & +------sp
px-----+ recombinants are 1+11= 12
+------sp recombinants are 9 +0 = 9
Total recombinants = 21
RF = (21/10000)*100 =0.21%
2. If single cross over (SCO) occurs between sp & +
Normal order= sp --------- + & + ------ cn
After cross over= sp ----- cn & +------ +
sp ----- cn recombinants are 1461 + 9 = 1470
+------ + recombinants are 1539 + 11= 1550
Total recombinants = 3020
RF = (3020/4197)*100 = 30.2%
3. If single cross over (SCO) occurs between px & cn
Normal order= px-------- + & +------ cn
After cross over= px-----cn & +------+
px-----cn recombinants are 1461+1= 1467
+------+ recombinants are 1539+0= 1539
Total recombinants = 3006
RF = (3006/4197)*100 = 30.06%
% RF = Map unit distance
The order of genes is -----
sp----0.21 m.u.---px----------30.06 m.u.------------cn
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