Can someone help me solve this 2 questions step by step please. 1) A 2.71kg bloc

Question

Can someone help me solve this 2 questions step by step please.

1) A 2.71kg block traveling right at 3.46m/s collides with a 5.80kgblock traveling left at 1.93m/s. After the collision the 2.71kgblock bounces back and is traveling left at 4.01m/s. What is thespeed and direction of the 5.80kg block after the collision? Wasenergy lost or gained in the collision? Was type of collision wasit?

2) A 3.20kg block slide down a 2.38m high ramp into a 8.30kg block.How fast are the two blocks going after an elastic collision? Howfar back up the incline does the smaller mass go?


Thank You for your help!

Explanation / Answer

1) should be an elastic collision because the two objects do notstick together. In that case, the kinetic energy should be conserved. we set up for momentum conservation: call the fist block A, thesecond B, before the collision '1', and after '2' then, mAvA1 +mBvB1 = mAvA2 +mBvB2 you want to find vB2, so rearrange and fill all thenumbers in and compute make sure to enter velocity to the left as negative numbers then you will know all velocities and masses, and you can calculatethe system kinetic energies: 1/2 mA vA12 + 1/2 mBvB12 versus 1/2 mAvA22 + 1/2 mBvB22

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