Two particles P and Q are released from rest 1.0 m apart. P has amass of 0.10kg,

Question

Two particles P and Q are released from rest 1.0 m apart. P has amass of 0.10kg, and Q a mass of 0.30 kg. P and Q attract each otherwith a constant force of 1.0 x 10^-2 N. No external forces act onthe system. What is the speed of the center of mass of P and Q when theseparation is 0.50m. At what distance from P's original position dothe particles collide? What is the speed of the center of mass of P and Q when theseparation is 0.50m. At what distance from P's original position dothe particles collide?

Explanation / Answer

according to work energy theorem, asthere is no external force acting on the system, the centerof mass is at rest. force with which they attract each other is 1*102N. let at x distance from P's original position theparticles collide,at the time t. acceleration of particle 0.1kg isF/m=1000m/s2. acceleration of particle 0.3kg isF/m=333.33m/s2. putting the values in equation s=ut+1/2at2 for both theparticle end equating them for x we can find the distance.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.