An astronaut performs a simple experiment in the \"weightless\"environment of a

Question

An astronaut performs a simple experiment in the "weightless"environment of a space station, intended for television broadcastto elementary school classrooms around the world. By combing herhair, she is able to charge a flat comb so that, in the vicinity ofthe comb, there is an approximately uniform electric field ofstrength E=900 N/C. She places the comb 4.00 cm away from a clumpof small paper dots, inducing a nonuniform distribution of chargein the clump so that one of the dots becomes charged and breaksaway, accelerating toward the comb. If the paper dot has a mass of2.95x10-4 kg and a charge of magnitude 3.50C, howfast is it going when it strikes the comb? I know I need to find the final velocity. I believe theformula I need to use for this is: vf2 =vi2 + 2ax. My question is: how do Ifind the final velocity of the paper dot traveling toward thecomb? An astronaut performs a simple experiment in the "weightless"environment of a space station, intended for television broadcastto elementary school classrooms around the world. By combing herhair, she is able to charge a flat comb so that, in the vicinity ofthe comb, there is an approximately uniform electric field ofstrength E=900 N/C. She places the comb 4.00 cm away from a clumpof small paper dots, inducing a nonuniform distribution of chargein the clump so that one of the dots becomes charged and breaksaway, accelerating toward the comb. If the paper dot has a mass of2.95x10-4 kg and a charge of magnitude 3.50C, howfast is it going when it strikes the comb? I know I need to find the final velocity. I believe theformula I need to use for this is: vf2 =vi2 + 2ax. My question is: how do Ifind the final velocity of the paper dot traveling toward thecomb?

Explanation / Answer

We know that                F = E q                   = 900 * 3.50 x 10-6                   = 3.15 x 10-3 N and we also have         F = ma ==> a = F / m              = 3.15*10-3 N / 2.95×104 kg              =10.678 m/s2 Using relation basic kinematic relation we have        vf2 = vi2 +2ax            = 0 + 2 * 10.678 * 0.04 ==> vf = 0.924 m/s

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