You are given two resistors, an ammeter, a voltmeter, and a voltage source. By c

Question

You are given two resistors, an ammeter, a voltmeter, and a voltage source. By connecting each resistor singly to the voltage source and taking voltage difference and current measurements on the single resistor, you find the following data for each resistor:


Resistor Voltage (V) Current (mA)
1            4.5              30.2
2            3.72             9.3


Using this data, first find the resistance of each resistor and then calculate the following:


(a) The current that would pass through the network of resistors if they were arranged in series and connected to an 8.7 V voltage source.
I series =

(b) The current through the circuit if the resistors were arranged in parallel and connected to the same 8.7 V source from part (a).
I parallel =

Explanation / Answer

To fined the values of resistances: Let us name the first resistance as R1 and the second as R2.
We know Resistance = Voltage/Current R1 = 4.5/(30.2x10-3 ) = 0.149kO = 149O R2=3.72/(9.3x10-3) = 0.400kO=400O (a) Resistances are connected in series. Total resistance Rtotal = R1+R2 = 149 + 400 = 549O Current = voltage/Rtotal = 8.7/549 = 15.8mA
(b) Resistances are connected in parallel. Rtotal = R1xR2/(R1+R2) = 149x400/(149+400) = 108.56O Current = Voltage/Rtotal = 8.7/108.56 = 80.14mA

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