You are given two resistors, an ammeter, a voltmeter, and a voltage source. By c

Question

You are given two resistors, an ammeter, a voltmeter, and a voltage source. By connecting each resistor singly to the voltage source and taking voltage difference and current measurements on the single resistor, you find the following data for each resistor:

Resistor Voltage (V) Current (mA)
1 3.88 43.6
2 4.48 14.45

Using this data, first find the resistance of each resistor and then calculate the following:

(a) The current that would pass through the network of resistors if they were arranged in series and connected to an 7.65 V voltage source.
Iseries =

(b) The current through the circuit if the resistors were arranged in parallel and connected to the same 7.65 V source from part (a).
Iparallel =

Explanation / Answer

emf of the battery = E, resistances: R1 and R2 V1 = 3.88 V, I1 = 43.6 mA, so R1 = V1/I1 = 89.0 Ohm V2 = 4.48 V, I2 = 14.45 mA, so R2 = V2/I2 = 310 Ohm (a) E = 7.65 V Iseries = E/(R1 + R2) = 19.17 mA (b) equivalent R = R1*R2/(R1 + R2) = 69.15 Ohm Iparallel = E/R = 110.6 mA

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