A 35.0 g bullet is shot n 291 m/s into a 2.00 kg block of wood that is lining on

Question

A 35.0 g bullet is shot n 291 m/s into a 2.00 kg block of wood that is lining on a rough table The bullet socks in the block and the block/bullet slide on the rough table ( mu k = 0.85), coming to rest on the table top. Compute the speed of the block/bullet just alter the collision. Note: friction doesn't affect this answer because the bullet and block reach a common speed in a very short distance, well before friction has had a chance to a fleet the block speed. Compute the magnitude and direction of the force of friction acting on the block/bullet as they side across the rough table. Compute the acceleration (i.e., deceleration) of the block/bullet as they slide across the rough table. Compute the distance the block/bullet slides before coming to rest. Answer

Explanation / Answer

μa) the initial momentum of the bullet = mv = 0.035*291. After collision, the momentum is transfered to block/bullet. so the velocity of the block = p /(m1+m2) = 0.035*291/(2+0.035) = 5.00 m/s

b) frictional force is to the left, F =μmg = 0.85 * 2.035 *9.8 = 17.0 N

c) from F = ma, we know a = F/m = -17.0 / 2.035 = -8.35 m/s^2. The negative sign just indicates the acceleration is to the left.

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