A solid metal ball of radius 1.1 cm bearing a charge of -16 nC is located near a

Question

A solid metal ball of radius 1.1 cm bearing a charge of -16 nC is located near a hollow plastic ball of radius 1.7 cm bearing a uniformly distributed charge of -8 nC (see the figure) on its outer surface. The distance between the centers of the balls is 11 cm.

Assume the +x axis runs to the right, the +y axis runs up and the +z axis is out.

What is the electric field at the center of the metal ball due only to the charges on the plastic ball?

= < X, Y, Z > N/C

What is the net electric field at the center of the metal ball?

= < X,Y,Z > N/C

What is the electric field at the center of the metal ball due only to the charges on the surface of the metal ball?

= < X,Y,Z> N/C

Explanation / Answer

Note:   fig wasn't given

charge on the solid metal ball = Q1= - 16 nC = - 16 *10^-9   C

distance betwwen them   = R = 11 cm = 0.11 m

charge on the halloe plastic ball = Q2 = - 8 nC = - 8 *10^- 9 C

(a)

electric field at the center of the metal ball due only to the charges on the plastic ball

   is     E = K Q/R^2

   where K is the constant = 9*10^9 Nm^2 /C^2

     thus , E = (9 *10^9)   (16 *10^-9  ) /(0.11)^2

                   =  11900.8 N/C

(b)

What is the net electric field at the center of the metal ball   is alsohave the same value

   E =    K Q/R^2

      =  

E = (9 *10^9)   (16 *10^-9  ) /(0.11)^2

                   =  11900.8 N/C

(c)

Electric field at the center of the metal ball = 0 N/C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.