A solid metal ball of radius 1.1 cm bearing a charge of -19 nC is located near a

Question

A solid metal ball of radius 1.1 cm bearing a charge of -19 nC is located near a hollow plastic ball of radius 2.1 cm bearing a uniformly distributed charge of -9 nC (see the figure) on its outer surface. The distance between the centers of the balls is 8 cm.
Assume the +x axis runs to the right, the +y axis runs up and the +z axis is out.

What is the electric field at the center of the metal ball due only to the charges on the plastic ball?
= < , , > N/C
What is the net electric field at the center of the metal ball?
= < , , > N/C
What is the electric field at the center of the metal ball due only to the charges on the surface of the metal ball?
= < , , > N/C

Explanation / Answer

(a)

   is     E = K Q/R2

   where K is the constant = 9x10^9 Nm^2 /C^2

     thus , E = (9 x10^9)   (19 x10^-9  ) /(0.011)^2

                   =  1413223.14 N/C

(b)

   E =    K Q/R^2

    E = (9 x10^9)   (19 x10^-9  ) /(0.011)^2

                   = 1413223.14 N/C

(c)

Electric field at the center of the metal ball = 0 N/C

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