A beam is subjected to equal 25 kip-ft bending moments, as shown. The cross-sect

Question

A beam is subjected to equal 25 kip-ft bending moments, as shown. The cross-sectional dimensions of the beam are shown in the figure on the right. The centroid location is located at 4.4 in from the bottom of the cross-section and the moment of inertia about the z axis is I.-543.4 in Solve for the normal stress (in ksi) due to bending at the top and bottom of the section (state tension or compression) plot a distribution of stress over the cross-section. a) b) 1 in 25 kips-ft in. 25 kips-ft 9 in. in. 8 in

Explanation / Answer

a) Moment in beam=25 kip-ft = 300kip-in

Moment of inertia of section = 543.4in4

ytop = 12-4.4=7.6in

ybottom=4.4 in

Bending stress at top = 300*7.6/543.4=4.19 ksi(tension)

Bending stress at bottom = 300*4.4/543.4=2.43 ksi(compression)

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