13. (30 pts) You have been tasked to design a concrete mix for a warehouse floor
ID: 1714620 • Letter: 1
Question
13. (30 pts) You have been tasked to design a concrete mix for a warehouse floor slab. The slab is 8" thick (to accommodate the heavy floor loads), so you have chosen to use a coarse aggregate with a 2" NMAS. You need a slump of 3-4" without admixtures and a design compressive strength (f'e) of 4800 psi. Since this will be indoors, you do not need to add air entrainment. The coarse aggregate is a subangular stone and the fine aggregate is a river sand that meets the ASTM C33 specification. The aggregate has the following properties: Coarse Fine Aggregate Aggregate Unit Weight (Ib/ft3) Bulk Specific Gravity Apparent Specific Gravity Fineness Modulus Absorption 102 2.66 2.68 106 2.62 2.65 2.90 1.3% 0.9% Determine a trial mix design using the estimated weight method. DO NOT ADJUST FOR ABSORPTION OR MOISTURE CONTENT. You must show all of your work. Spreadsheer solutions are not acceptable. Continue your calculations on the next page if necessary.Explanation / Answer
Trial mix using estimated weight approach as per ACI
Nominal maximum aggregate size (NMAS) = 2"
Mixing water as per table 10.9 = 285 lb/ yd3
Let us assume 1 yd3 total volume of mix
Thus mixing water required = 285 lb
Now w/c by weight as per table 10.3 = 0.57-((0.57-0.48)*(4800-4000)/(5000-4000)) = 0.498
Thus cement content= 285/ 0.498 = 572.289 lb
Thus volume of cement assuming specific gravity of 3.15 is = 572.289/(3.15*62.4) = 2.91 ft3
Volume of water = 285/ 62.4 = 4.567 ft3
Volume of air = zero ( non air entrapped)
Thus volume of coarse and fine aggregates = 27- 2.91-4.567-0= 19.523
As per table 10.5 the volume of coarse aggregates based on fineness modulus of fine aggregates =0.74- ((0.74-0.72)*(2.9-2.8)/(3-2.8))=0.73 *19.523 = 14.25 ft3
Thus volume of fine aggregates = 27- 2.91-4.567-0-14.25 = 5.273 ft3
Thus weight of water = 285 lb
Weight of cement = 572.289 lb
Weight of fine aggregates = 106*5.273 = 558.938 lb
Weight of coarse aggregates = 102*14.25 = 1453.5 lb
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